文章 2023-01-05 来自:开发者社区

LeetCode 232. Implement Queue using Stacks

DescriptionImplement the following operations of a queue using stacks.push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front of queue.peek() -- Get the front elemen....

LeetCode 232. Implement Queue using Stacks
文章 2022-04-15 来自:开发者社区

[LeetCode]232.Implement Queue using Stacks

题目 Implement the following operations of a queue using stacks. push(x) – Push element x to the back of queue. pop() – Removes the element from in front of queue. peek() – Get the front element. ...

文章 2022-02-17 来自:开发者社区

LeetCode 232:用栈实现队列 Implement Queue using Stacks

题目: 使用栈实现队列的下列操作: push(x) -- 将一个元素放入队列的尾部。 pop() -- 从队列首部移除元素。 peek() -- 返回队列首部的元素。 empty() -- 返回队列是否为空。 Implement the following operations of a queue using stacks. push(x) -- Push element x to th...

文章 2022-02-17 来自:开发者社区

LeetCode 232 Implement Queue using Stacks(用栈来实现队列)(*)

版权声明:转载请联系本人,感谢配合!本站地址:http://blog.csdn.net/nomasp https://blog.csdn.net/NoMasp/article/details/50550978 翻译 用栈来实现队列的下列操作。 push(x) —— 将元素x写入到队列的尾部 pop(...

文章 2022-02-16 来自:开发者社区

[LeetCode] Implement Queue using Stacks 用栈来实现队列

Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empt.....

文章 2022-02-16 来自:开发者社区

[LeetCode] Implement Queue using Stacks

A classic interview question. This link has a nice explanation of the idea using two stacks and its amortized time complexity. I use the same idea in my code, which is as follows. 1 class Queue { ...

文章 2022-02-15 来自:开发者社区

[LeetCode]--232. Implement Queue using Stacks

Implement the following operations of a queue using stacks. push(x) – Push element x to the back of queue. pop() – Removes the element from in front of queue. peek() – Get the front element. empt...

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