Elementui Tree 树形控件，将勾选选中的值放在list集合里面提交
要求：Elementui Tree 树形控件，将勾选选中的值放在list集合里面提交提交格式是这样的，也就是将勾选项放在一个数组里面，作为参数提交给后端即可。步骤：这里我用到了json本地的数据，因为掉接口数据，不太方便写demo，后面统一都用到mock，json数据了&...
Leetcode 114. Flatten Binary Tree to Linked List
题目意思很简单，就是把一棵二叉数转换为链表，虽然题目中没说以什么样的形式转换，但看下样例就很容易看出来，是以先序遍历的次序转换成链表。这里链表节点还是treenode，只不过它的左节点为空而已。 思路也很简单，先把root的左子树（如有）变成单链表 leftlinkedlist&#...
二叉树(Binary Tree)的二叉链表(Binary Linked List)实现
BinaryNode.h#ifndef __BINARYNODE_H__ #define __BINARYNODE_H__ template <class T> class BinaryNode { public: T data; BinaryNode<T> *lchild, *rchild; }; #endifBinaryTree.h#ifndef __...
[LeetCode]114.Flatten Binary Tree to Linked List
【题目】 Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 ...
LintCode: Flatten Binary Tree to Linked List
C++ Traverse 1 /** 2 * Definition of TreeNode: 3 * class TreeNode { 4 * public: 5 * int val; 6 * TreeNode *left, *right; 7 * TreeNode(int val) { 8 * this->val ...
[LeetCode] Flatten Binary Tree to Linked List 将二叉树展开成链表
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 ...
[LintCode] Flatten Binary Tree to Linked List 将二叉树展开成链表
$stringUtil.substring( $!{XssContent1.description},200)...
LeetCode:114_Flatten Binary Tree to Linked List | 将一棵二叉树变成链表的形式 | Medium
要求：Given a binary tree, flatten it to a linked list in-place.将二叉树转化为平坦序列的树。比如： 结题思路： 该题有个提示，转化后的树的序列正好是二叉树前序遍历所得到的序列，所以，该题第一个思路就是利用前序遍历的方式来做。 第二个思路：我们可以利用递归的思路，先对根节点进行处理，将root的左子树放到右子树，在将左子树中的最右端节点...
[LeetCode] Flatten Binary Tree to Linked List
This problem seems to be tricky at first glance. However, if you know Morris traversal, it is just the preorder case of Morris traversal and the code is really short. 1 void flatten(TreeNode* r...
Flatten Binary Tree to Linked List
Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2...
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